algorithm reversing

[mindoverflow]

I'm working on this pseudocode trying to find the correct input for the expected calculated value (i'm not sure if i can call it a checksum). I can't focus enough to generate the reverse algorithm, then any kind of help is appreciated.

I may start with the value 2602618273338008543 in v20 and xor back on the random generated input but i think the end result would be too big to be xored to zero with a single byte.

PS: I commented some lines that i suppose have no effect on the computation.

Thank you.

    v20 = 0i64;
    // salt table
    v28="a#+EJK45fe/efJWDSlesfGe03saHHFddfdq2gr%a3ß0jm2ÜcFEF!JKMÄrAfim+wqe=WD=?f3jDKefDJ§W?)JöSeAEFj_LIeJDF"; // salt table
    input = new byte[32] { 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00 };
    for ( j = 0; j < 200; ++j )
    {
      v24 = (v20 + j) % 60 + 1; // 0x3c
      v15 = input[7 * j % 15];
      if ( v24 == 32 ) // 0x20
        v15 = __PAIR__(v15, HIDWORD(v15));
      if ( v24 == 31 ) // 0x1f
      {
        // v22 = v24 & 31; // 0x1f
        // v11 = HIDWORD(v15);
        // v8 = v15;
        v1 = (unsigned __int64)(v15 << (v24 & 0x1F)) >> 32;
        LODWORD(v15) = __PAIR__((unsigned int)v15, HIDWORD(v15)) << (v24 & 0x1F) >> 32;
        HIDWORD(v15) = v1;
      }
      // v6 = v15;
      v20 += v15;
      v25 = (v20 ^ (unsigned __int64)j) % 62 + 2; // 0x3e + 2
      v2 = (v20 - j) % 91;  // 0x5Bui64
      LODWORD(v16) = *(int *)((char *)&v28 + v2);
      HIDWORD(v16) = *(int *)((char *)&v29 + v2); // &v29=&v28-4
      if ( v25 & 32 ) // 0x20
        v16 = __PAIR__(v16, HIDWORD(v16));
      if ( v25 & 31 ) // 0x1f
      {
        // v21 = v25 & 31; // 0x1f
        // v9 = HIDWORD(v16);
        // v10 = v16;
        v3 = (unsigned __int64)(v16 << (v25 & 0x1F)) >> 32;
        LODWORD(v16) = __PAIR__((unsigned int)v16, HIDWORD(v16)) << (v25 & 0x1F) >> 32;
        HIDWORD(v16) = v3;
      }
      v7 = v16;
      v20 ^= v16;
    }
    if ( (_DWORD)v20 == -922952045 && HIDWORD(v20) == -902699940 || v20 == 2602618273338008543i64 )
      v23 = 1;
  }